Chapter 2 - Real Numbers - Chapter 2 Review Problem Set - Page 88: 23

$= 1$

We first multiply the numerators and the denominators of the fractions by each other. Then, we simplify the fractions to obtain: $(\frac{-4y}{3x})(-\frac{3x}{4y})$ $(\frac{-4y}{3x})(\frac{-3x}{4y})$ $= \frac{-4y(-3x)}{3x(4y)}$ $= \frac{12xy}{12xy}$ $= 1$