Chapter 2 - Real Numbers - Chapter 2 Review Problem Set - Page 88: 13

$= -\frac{1}{64}$

Recall, because of PEDMAS, we consider what is inside of parenthesis first, and then we consider the exponent. Thus, we obtain: $(\frac{1}{4}-\frac{1}{2})^{3}$ $= (\frac{1}{4}-\frac{2}{4})^{3}$ $= (-\frac{1}{4})^{3}$ $= -\frac{1}{4^{3}}$ $= -\frac{1}{64}$