Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.2 - 3 x 3 Systems of Equations - Problem Set 11.2 - Page 484: 20

Answer

The sweater cost 14 dollars, the blouse cost 10 dollars, and the skirt cost 48 dollars.

Work Step by Step

We call w the cost of a sweater, b the cost of a blouse, and k the cost of a skirt. Thus, we know: $ k + w = 6b + 2 \\ k = 2(b + w) \\ k + b + w = 72$ First, using equations two and three, we substitute k/2 for b+w: $ k + k/2 = 72 \\ k = 48$ This means: $ 24 = b+ w \\ w = 24 -b$ We plug this into equation one to find: $ 48 + 24 - b = 6b +2 \\ 7b = 70 \\ b = 10$ Thus: $w = 24 - b = 24 - 10 = 14$
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