Answer
{$-13,1$}
Work Step by Step
Factoring the equation and setting the factors equal to zero, we obtain:
$t^{2}+12t+36=49$
$t^{2}+12t+36-49=0$
$t^{2}+12t-13=0$
$t^{2}-1t+13t-13=0$
$t(t-1)+13(t-1)=0$
$(t-1)(t+13)=0$
$(t-1)=0$ or $(t+13)=0$
$t=1$ or $t=-13$
Therefore, the solution set is {$-13,1$}.
