Answer
{$-7,2$}
Work Step by Step
Factoring the equation and setting the factors equal to zero, we obtain:
$2x^{2}+10x-28=0$
$2x^{2}-4x+14x-28=0$
$2x(x-2)+14(x-2)=0$
$(x-2)(2x+14)=0$
$(x-2)=0$ or $(2x+14)=0$
$x=2$ or $x=-\frac{14}{2}$
$x=2$ or $x=-7$
Therefore, the solution set is {$-7,2$}.
