Answer
True
Work Step by Step
We solve the equation using the square root property:
$(3x+4)^{2}=64$
$\sqrt {(3x+4)^{2}}=\sqrt {64}$
$3x+4=\pm 8$
$3x+4=8$ or $3x+4=-8$
$3x=4$ or $3x=-12$
$x=\frac{4}{3}$ or $x=-4$
Therefore, the solution set of the equation is {$-4,\frac{4}{3}$}. Since both of these numbers are rational, the statement of the question is true.
