Answer
False
Work Step by Step
We solve the equation using the square root property:
$(x-6)^{2}=0$
$\sqrt {(x-6)^{2}}=\sqrt 0$
$x-6=\pm 0$
$x-6=0$ or $x-6=0$
$x=6$ or $x=6$
Therefore, the solution set of the equation is {$6$}. It can be seen that the solution set consists of only one integer, and as a result, the statement of the question is false.
