Answer
$\begin{bmatrix}
0 & 0 & 0\\
0 & 0 & 0\\
0 & 0 & 0\\
\end{bmatrix}$
Work Step by Step
Make $a_{ij}=0$, if $i\lt j$. That is,
$a_{12}=a_{13}=a_{23}=0$
Also, $a_{ji}=-a_{ij}$. So:
$a_{21}=a_{12}=0$
$a_{31}=a_{13}=0$
$a_{32}=a_{23}=0$
The elements, $a_{ii}$, of the main diagonal must be equal to zero because $a_{ii}=-a_{ii}$
The only possibility is:
$\begin{bmatrix}
0 & 0 & 0\\
0 & 0 & 0\\
0 & 0 & 0\\
\end{bmatrix}$