Answer
vertical asymptotes: $x=-0.2$ and $x=1.5$
horizontal asymptote: $y=0.1$
Work Step by Step
Vertical asymptotes occur where the denominator is zero. Thus, we set the denominator to zero and solve for the $x$ values to find the vertical asymptotes:
$(5x+1)(2x-3)=0$
$x=-0.2$ and $x=1.5$
Thus the vertical asymptotes are $x=-0.2$ and $x=1.5$
Here, the degrees of the numerator and the denominator are the same. Thus, the horizontal asymptote is the quotient of the leading coefficients:
$y=\frac{1}{10}=0.1$
