Answer
Vertical asymptotes: $\qquad x=-1,\ \quad x=1$.
Horizontal asymptote: $\qquad y=0$.
Work Step by Step
Use the procedure "Finding asymptotes of rational functions" on page 336.
1.
The denominator is zero for
$x^{4}-1=0$
$(x^{2}+1)(x^{2}-1)=0$
$(x^{2}+1)(x-1)(x+1)=0$
$x=-1,\ \quad x=1 \qquad$( vertical asymptotes)
2.
The numerator has degree $n=2$,
the denominator has degree $m=4$
Since $n \lt m,\quad $the horizontal asymptote is $y=0.$
