Answer
x-intercepts: $-1$ and $2.$
y-intercept: $\displaystyle \frac{1}{3}.$
Work Step by Step
The y- intercept is the value $t(0)$, if defined.
$t(0)=\displaystyle \frac{0-0-2}{0-6}=\frac{1}{3}$
The x intercepts are values of x where $t(x)=0.$
$t(x)=0$ occurs when the numerator equals 0.
The numerator is zero for
$x^{2}-x-2=0$
Factor the trinomial $x^{2}+bx+c$ by searching for factors of c whose sum is $b$. We find $-2$ and $+1$.
$(x-2)(x+1)=0$
$x=-1, x=2$
