College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Chapter 2 Review - Exercises - Page 268: 41

Answer

Yes.

Work Step by Step

We are given: $x^{3}-y^{3}=27$ We solve for $y$: $ y^{3}=x^{3}-27$ $ y=(x^{3}-27)^{1/3}$ We see that this is indeed a function, since the cubic root provides only one $y$ value for each $x$ value.
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