Answer
The solution is $(-1,-7)$.
Work Step by Step
The given system is
$y=x^2+4x-4$ ...... (1)
$y=2x-5$ ...... (2)
Graph is each equation.
The point of intersection is $A=(-1,-7)$.
Check: $(x,y)=(-1,-7)$
Equation (1).
$\Rightarrow y=x^2+4x-4$
$\Rightarrow -7=(-1)^2+4(-1)-4$
$\Rightarrow -7=1-4-4$
$\Rightarrow -7=1-8$
$\Rightarrow -7=-7$
True.
Equation (2).
$\Rightarrow y=2x-5$
$\Rightarrow -7=2(-1)-5$
$\Rightarrow -7=-2-5$
$\Rightarrow -7=-7$
True.
Hence, the solution is $(-1,-7)$.
