Answer
$2\sqrt{3}$
Work Step by Step
The given expression is
$=\sqrt{b^2-4ac}$
The given values are
$a=3,b=-6$ and $c=2$
Substitute all the values into the expression.
$=\sqrt{(-6)^2-4(3)(2)}$
Simplify.
$=\sqrt{36-24}$
Subtract.
$=\sqrt{12}$
$=2\sqrt{3}$.
