Answer
$x=-1$ and $x=3$
Work Step by Step
The given equation is
$-x^2+2x+3=0$
From the given graph.
The $x-$intercepts are $-1$ and $3$.
Check $x=-1$.
$\Rightarrow -x^2+2x+3=0$
$\Rightarrow -(-1)^2+2(-1)+3=0$
$\Rightarrow -1-2+3=0$
$\Rightarrow -3+3=0$
$\Rightarrow 0=0$
True.
Check $x=3$.
$\Rightarrow -x^2+2x+3=0$
$\Rightarrow -(3)^2+2(3)+3=0$
$\Rightarrow -9+6+3=0$
$\Rightarrow -9+9=0$
$\Rightarrow 0=0$
True.
Hence, the solutions are $x=-1$ and $x=3$.
