Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Monitoring Progress - Page 482: 16

Answer

$\frac{\sqrt{6}}{3}y$.

Work Step by Step

The given expression is $=\sqrt{\frac{2y^2}{3}}$ Use quotient property of square roots. $=\frac{\sqrt{2y^2}}{\sqrt{3}}$ Multiply by $\frac{\sqrt{3}}{\sqrt{3}}$. $=\frac{\sqrt{2y^2}}{\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}$ Use product property of square roots. $=\frac{\sqrt{2y^2\cdot 3}}{\sqrt{3\cdot 3}}$ $=\frac{\sqrt{6y^2}}{\sqrt{3^2}}$ Use product property of square roots. $=\frac{\sqrt{6}\sqrt{y^2}}{\sqrt{3^2}}$ Simplify. $=\frac{\sqrt{6}}{3}y$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.