Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Monitoring Progress - Page 482: 15

Answer

$\frac{7\sqrt{2x}}{2x}$.

Work Step by Step

The given expression is $=\frac{7}{\sqrt{2x}}$ Multiply by $\frac{\sqrt{2x}}{\sqrt{2x}}$. $=\frac{7}{\sqrt{2x}}\cdot \frac{\sqrt{2x}}{\sqrt{2x}}$ Use product property of square roots. $=\frac{7\sqrt{2x}}{\sqrt{2x\cdot 2x}}$ $=\frac{7\sqrt{2x}}{\sqrt{(2x)^2}}$ Simplify. $=\frac{7\sqrt{2x}}{2x}$.
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