Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Monitoring Progress - Page 481: 10

Answer

$2x \sqrt[3]{2x}$.

Work Step by Step

The given expression is $=\sqrt[3]{16x^4}$ Factor as cube terms. $=\sqrt[3]{8x^3\cdot 2x}$ Use product property of cube roots. $=\sqrt[3]{8x^3}\cdot \sqrt[3]{2x}$ Use $8=2^3$. $=\sqrt[3]{2^3x^3}\cdot \sqrt[3]{2x}$ Use product property of cube roots. $=\sqrt[3]{2^3}\cdot \sqrt[3]{x^3}\cdot \sqrt[3]{2x}$ Simplify. $=2x \sqrt[3]{2x}$.
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