Answer
$y=x^2+7x+10$
Work Step by Step
Use the intercept form of a quadratic function:
$$y=a(x-p)(x-q)$$
Substitute $p=-2$, $q=-5$ and let $a=1$:
$$y=1(x-(-2))(x-(-5))$$ $$y=(x+2)(x+5)$$ $$y=x^2+7x+10$$
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