Answer
The signs of the zeros
Work Step by Step
The mistake is in the signs of the zeros ($x$-intercepts).
$$y=5(x+3)(x-2)$$
Rewrite as:
$$y=5(x-(-3))(x-2)$$
Now it is in the form $y=a(x-p)(x-q)$, so the zeros are $-3$ and $2$.
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 8 - Graphing Quadratic Functions - 8.5 - Using Intercept Form - Exercises - Page 456: 43
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