Answer
The function is neither even nor odd.
Work Step by Step
The given function is
$\Rightarrow n(x)=2x^2-7x+3$
Substitute $-x$ for $x$.
$\Rightarrow n(-x)=2(-x)^2-7(-x)+3$
Simplify.
$\Rightarrow n(-x)=2x^2+7x+3$
Because $n(-x)\neq-n(x)$ and $n(-x)\neq n(x)$, the function is neither even nor odd.
