Chapter 8 - Graphing Quadratic Functions - 8.3 - Graphing f(x) = ax^2 + bx + c - Exercises - Page 436: 3

The vertex is $(2,-1)$, the axis of symmetry is $x=2$ and the y-intercept is $(0,1)$.

It is clear from the graph that the vertex is $(2,-1)$, the axis of symmetry is $x=2$ and the y-intercept is $(0,1)$. The y-intercept is the point at which the graph cuts the y-axis (i.e., when $x=0$).