Answer
The axis of symmetry is $x=2$.
The vertex is $(2,4)$.
Work Step by Step
Comparing $f(x)=-6x^{2}+24x-20$ with $f(x)=ax^{2}+bx+c$, we see that $a=-6$ and $b=24$.
Axis of symmetry is given by
$x=-\frac{b}{2a}=-\frac{24}{2(-6)}=2$
The axis of symmetry is $x=2$.
As the axis of symmetry is $x=2$, the x-coordinate of the vertex is $2$.
We can use the function to find the y-coordinate.
$f(x)=-6x^{2}+24x-20$
$f(2)=-6(2)^{2}+24(2)-20=4$
The vertex is $(2,4)$.
