Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - Chapter Test - Page 413: 4

Answer

$h^2-13h+40$.

Work Step by Step

The given expression is $=(h-5)(h-8)$ Distribute $(h-8)$ to each term of $(h-5)$. $=h(h-8)-5(h-8)$ Use distributive property. $=h(h)+h(-8)-5(h)-5(-8)$ Multiply. $=h^2-8h-5h+40$ Combine like terms. $=h^2-13h+40$ Hence, the product is $h^2-13h+40$.
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