Answer
$( y-9)(y^2+1)$.
Work Step by Step
The given polynomial is
$= y^3-9y^2+y-9$
Group the terms.
$=( y^3-9y^2)+(y-9)$
Factor each group.
$=y^2( y-9)+1(y-9)$
Factor out $(y-9)$.
$=( y-9)(y^2+1)$
Hence, the complete factor of the polynomial is $( y-9)(y^2+1)$.
