Answer
$d=2,d=-6$ and $d=-8$.
Work Step by Step
The given equation is
$\Rightarrow (d-2)(d+6)(d+8)=0$
Use zero-product property rule.
$\Rightarrow d-2=0$ or $d+6=0$ or $d+8=0$
Solve for $x$.
$\Rightarrow d=2$ or $d=-6$ or $d=-8$
Check:-
$d=2$
$\Rightarrow (2-2)(2+6)(2+8)=0$
$\Rightarrow (0)(8)(10)=0$
$\Rightarrow 0=0$
True.
Check:-
$d=-6$
$\Rightarrow (-6-2)(-6+6)(-6+8)=0$
$\Rightarrow (-8)(0)(2)=0$
$\Rightarrow 0=0$
True.
Check:-
$d=-8$
$\Rightarrow (-8-2)(-8+6)(-8+8)=0$
$\Rightarrow (-10)(-2)(0)=0$
$\Rightarrow 0=0$
True.
Hence, the solutions are $d=2,d=-6$ and $d=-8$.
