Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.4 - Solving Polynomial Equations in Factored Form - Monitoring Progress - Page 379: 4

Answer

$s=-\frac{5}{3}$ and $s=-\frac{8}{5}$.

Work Step by Step

The given equation is $\Rightarrow (3s+5)(5s+8)=0$ Use zero-product property rule. $\Rightarrow 3s+5=0$ or $5s+8=0$ Solve for $s$. $\Rightarrow s=-\frac{5}{3}$ or $s=-\frac{8}{5}$ Check:- $s=-\frac{5}{3}$ $\Rightarrow (3(-\frac{5}{3})+5)(5(-\frac{5}{3})+8)=0$ $\Rightarrow (-5+5)(-\frac{25}{3}+8)=0$ $\Rightarrow 0(-\frac{1}{3})=0$ $\Rightarrow 0=0$ True. Check:- $s=-\frac{8}{5}$ $\Rightarrow (3(-\frac{8}{5})+5)(5(-\frac{8}{5})+8)=0$ $\Rightarrow (-\frac{24}{5}+5)(-8+8)=0$ $\Rightarrow (\frac{1}{5})(0)=0$ $\Rightarrow 0=0$ True. Hence, the solutions are $s=-\frac{5}{3}$ and $s=-\frac{8}{5}$.
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