Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.3 - Special Products of Polynomials - Exercises - Page 376: 43

Answer

The friend is incorrect. $\left(4\frac{1}{3}\right)^{2}$ is equal to $16\frac{25}{9}$ when evaluated using the square of a binomial pattern.

Work Step by Step

Using the square of a binomial pattern, we have $\left(4\frac{1}{3}\right)^{2}=\left(4+\frac{1}{3}\right)^{2}=4^{2}+2(4)\left(\frac{1}{3}\right)+\left(\frac{1}{3}\right)^{2}$ $=16+\frac{8}{3}+\frac{1}{9}=16+\frac{25}{9}=16\frac{25}{9}$. The friend is incorrect. He squared the integer part and the fraction part and placed the two results near each other.
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