Answer
$y^{6}+8y^{3}+16$
Work Step by Step
Using the square of a binomial pattern $(a+b)^{2}=a^{2}+b^{2}+2ab$, we obtain
$(y^{3}+4)^{2}=(y^{3})^{2}+4^{2}+2(y^{3})(4)$
$=y^{6}+8y^{3}+16$
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 7 - Polynomial Equations and Factoring - 7.3 - Special Products of Polynomials - Exercises - Page 376: 40
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