Answer
The roots are $y=0$, $y=8$ and $y=-\frac{1}{2}$
Work Step by Step
Given: $-3y(y-8)(2y+1)=0$
Using zero-product property, we have
$-3y=0$ or $y-8=0$ or $2y+1=0$
Solving for $y$, we get
$y=0$ or $y=8$ or $y=-\frac{1}{2}$
The roots are $y=0$, $y=8$ and $y=-\frac{1}{2}$
