Answer
The solutions are $p=-\frac{7}{3}$, $p=\frac{7}{3}$ and $p=-8$.
Work Step by Step
Given: $(3p+7)(3p-7)(p+8)=0$
Using zero-product property, we have
$3p+7=0$ or $3p-7=0$ or $p+8=0$.
Solving for $p$, we have
$p=-\frac{7}{3}$ or $p=\frac{7}{3}$ or $p=-8$.
The solutions are $p=-\frac{7}{3}$, $p=\frac{7}{3}$ and $p=-8$.
