Answer
The solution is $(-4,0)$.
Work Step by Step
The given system of linear equation is
$x-4y=-4$ ...... (1)
$-3x-4y=12$ ...... (2)
Graph each equation.
The intersection point is $(-4,0)$.
Check the intersection point.
Equation 1:
$\Rightarrow x-4y=-4$
$\Rightarrow -4-4(0)=-4$
$\Rightarrow -4=-4$
True.
Equation 2:
$\Rightarrow -3x-4y=12$
$\Rightarrow -3(-4)-4(0)=12$
$\Rightarrow 12+0=12$
$\Rightarrow 12=12$
True.
The solution is $(-4,0)$.
