Answer
The solution is $(-9,-1)$.
Work Step by Step
The given system of linear equation is
$y=\frac{1}{3}x+2$ ...... (1)
$y=\frac{2}{3}x+5$ ...... (2)
Graph each equation.
The intersection point is $(-9,-1)$.
Check the intersection point.
Equation 1:
$\Rightarrow y=\frac{1}{3}x+2$
$\Rightarrow -1=\frac{1}{3}(-9)+2$
$\Rightarrow -1=-3+2$
$\Rightarrow -1=-1$
True.
Equation 2:
$\Rightarrow y=\frac{2}{3}x+5$
$\Rightarrow -1=\frac{2}{3}(-9)+5$
$\Rightarrow -1=-6+5$
$\Rightarrow -1=-1$
True.
The solution is $(-9,-1)$.
