Answer
$y-0=-\frac{2}{3}(x-4)$
Work Step by Step
Given: Slope $m=-\frac{2}{3}$
and $(x_{1},y_{1})=(4,0)$
Point-slope form is $y-y_{1}=m(x-x_{1})$
Substituting the values of $m$ and $b$, we get
$y-0=-\frac{2}{3}(x-4)$ which is the equation of line in the point-slope form.
