Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - Chapter Review - Page 165: 15

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow -12x-3y=36$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow -12x-3(0)=36$ Simplify. $\Rightarrow -12x=36$ Divide each side by $-12$. $\Rightarrow \frac{-12x}{-12}=\frac{36}{-12}$ Simplify. $\Rightarrow x=-3$ The $x-$ intercept is $-3$, so plot the point $A=(-3,0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow -12(0)-3y=36$ Simplify. $\Rightarrow 0-3y=36$ $\Rightarrow -3y=36$ Divide each side by $-3$. $\Rightarrow \frac{-3y}{-3}=\frac{36}{-3}$ Simplify. $\Rightarrow y=-12$ The $y-$ intercept is $-12$, so plot the point $B=(0,-12)$ Draw a line through the points $A$ and $B$.
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