Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - Chapter Review - Page 165: 14

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow 8x-4y=16$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow 8x-4(0)=16$ Simplify. $\Rightarrow 8x=16$ Divide each side by $8$. $\Rightarrow \frac{8x}{8}=\frac{16}{8}$ Simplify. $\Rightarrow x=2$ The $x-$ intercept is $2$, so plot the point $A=(2,0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow 8(0)-4y=16$ Simplify. $\Rightarrow 0-4y=16$ $\Rightarrow -4y=16$ Divide each side by $-4$. $\Rightarrow \frac{-4y}{-4}=\frac{16}{-4}$ Simplify. $\Rightarrow y=-4$ The $y-$ intercept is $-4$, so plot the point $B=(0,-4)$ Draw a line through the points $A$ and $B$.
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