Answer
All real numbers are solutions.
The graph is shown below.
Work Step by Step
The given inequality is
$\Rightarrow -4|6b-8|\leq 12$
Divide each side by $-4$. Reverse the inequality symbol.
$\Rightarrow \frac{-4|6b-8|}{-4}\geq \frac{12}{-4}$
Simplify.
$\Rightarrow |6b-8|\geq -3$
The absolute value of an expression must be greater than or equal to zero.
The expression $|6b-8|$ will always be greater than $-3$.
Hence, all real numbers are solutions.
