Answer
All real numbers are solutions.
The graph is shown below.
Work Step by Step
The given inequality is
$\Rightarrow |3j-1|+6\gt 0$
Subtract $6$ from each side.
$\Rightarrow |3j-1|+6-6\gt 0-6$
Simplify.
$\Rightarrow |3j-1|\gt -6$
The absolute value of an expression must be greater than or equal to zero.
The expression $|3j-1|$ will always be greater than $-6$.
Hence, all real numbers are solutions.
