Answer
$ b\geq -9$
The graph is shown below.
Work Step by Step
The given inequality is
$\Rightarrow 15(\frac{1}{3}b+3)\leq 6(b+9)$
Use distributive property.
$\Rightarrow 5b+45\leq 6b+54$
Add $-54-5b$ to each side.
$\Rightarrow 5b+45-54-5b\leq 6b+54-54-5b$
Simplify.
$\Rightarrow -9\leq b$
Hence, the solution is $ b\geq -9$.
Use a close circle because $-9$ is a solution.
Shade the number line on the right side.
