Answer
$ r\geq -12$
The graph is shown below.
Work Step by Step
The given inequality is
$\Rightarrow 3+\frac{r}{-4}\leq 6$
Subtract $3$ from each side.
$\Rightarrow 3+\frac{r}{-4}-3\leq 6-3$
Simplify.
$\Rightarrow \frac{r}{-4}\leq 3$
Multiply each side by $-4$. Reverse the inequality symbol.
$\Rightarrow -4\cdot (\frac{r}{-4})\geq -4\cdot 3$
Simplify.
$\Rightarrow r\geq -12$
Hence, the solution is $ r\geq -12$.
Use a close circle because $-12$ is a solution.
Shade the number line on the right side.
