Answer
$\frac{1}{2}(cos~100°+i~sin~100°)$
Work Step by Step
$\frac{cos~150°+i~sin~150°}{2(cos~50°+i~sin~50°))}=\frac{e^{i150°}}{2e^{i50°}}=\frac{1}{2}e^{i(150°-50°)}=\frac{1}{2}e^{i100°}=\frac{1}{2}(cos~100°+i~sin~100°)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 8 - Review Exercises - Page 618: 120
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