Answer
$\frac{3}{2}+\frac{3}{2}i$
Work Step by Step
Add the complex numbers and divide the result by 2:
$\frac{(2-i)+(1+4i)}{2}=\frac{(2+1)+(-1+4)i}{2}=\frac{3+3i}{2}=\frac{3}{2}+\frac{3}{2}i$
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