Answer
The magnitude is $1$.
Work Step by Step
Our aim is to show the magnitude is $1$.
Therefore, $\sqrt {(\cos\theta)^2+(\sin \theta)^2}=\sqrt 1=1$
This means that it is always a unit vector for any value of $\theta$.
Q.E.D.
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 8 - 8.3 - Vectors in the Plane - 8.3 Exercises - Page 588: 101
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