Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Chapter Test - Page 554: 6

Answer

$sec^{2}(x)tan^{2}(x) + sec^{2}(x) = sec^{4}(x)$ $sec^{2}(x) (tan^{2}(x) + 1)$ = $sec^{4}(x)$ $sec^{2}(x)$$sec^{2}(x)$ = $sec^{4}(x)$ $sec^{4}(x) = sec^{4}(x)$

Work Step by Step

Note: $tan^{2}(x) + 1 = sec^{2}(x)$ $sec^{2}(x)tan^{2}(x) + sec^{2}(x) = sec^{4}(x)$ Factor the expression: $sec^{2}(x) (tan^{2}(x) + 1)$ = $sec^{4}(x)$ Using the above note: $sec^{2}(x)$$sec^{2}(x)$ = $sec^{4}(x)$ $sec^{4}(x) = sec^{4}(x)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.