Answer
$1$
Work Step by Step
We know that $\sin^2 x+\cos^2 x=1$
$\csc^2 \beta (1-\csc^2 \beta)=\csc^2 \beta \sin^2 \beta$
or, $=(\dfrac{1}{\sin^2 \beta}) \times \sin^2 \beta$
or, $\csc^2 \beta (1-\csc^2 \beta)=1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Chapter Test - Page 554: 2
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
