Answer
$sin~100°~cos~40°-cos~100°~sin~40°=\frac{\sqrt 3}{2}$
Work Step by Step
$sin(u-v)=sin~u~cos~v-cos~u~sin~v$
$sin~100°~cos~40°-cos~100°~sin~40°=sin(100°-40°)=sin~60°=\frac{\sqrt 3}{2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.4 - Sum and Difference Formulas - 7.4 Exercises - Page 538: 38
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