Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.4 - Sum and Difference Formulas - 7.4 Exercises - Page 538: 32

Answer

$\frac{tan~1.1-tan~4.6}{1+tan~1.1~tan~4.6}=-tan~3.5$

Work Step by Step

$tan(u-v)=\frac{tan~u-tan~v}{1+tan~u~tan~v}$ $tan(-u)=-tan~u$ $\frac{tan~1.1-tan~4.6}{1+tan~1.1~tan~4.6}=tan(1.1-4.6)=tan(-3.5)=-tan~3.5$
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