Answer
$\frac{tan~1.1-tan~4.6}{1+tan~1.1~tan~4.6}=-tan~3.5$
Work Step by Step
$tan(u-v)=\frac{tan~u-tan~v}{1+tan~u~tan~v}$
$tan(-u)=-tan~u$
$\frac{tan~1.1-tan~4.6}{1+tan~1.1~tan~4.6}=tan(1.1-4.6)=tan(-3.5)=-tan~3.5$
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