Answer
False.
$tan~x^2=tan(x·x)$
$tan^2x=tan~x~tan~x$
Work Step by Step
Notice that $tan^2x\geq0$ for any $x$ in the domain of $tan^2x$
But, $tan(\frac{\sqrt {3\pi}}{2})^2=tan\frac{3\pi}{4}=-1\lt0$
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