Answer
Identity is verified.
$tan^2x~sec^4x=(tan^2x+tan^4x)sec^2$
Work Step by Step
We know that:
$1+tan^2x=sec^2x$
Start at the right side of the equation:
$(tan^2x+tan^4x)sec^2=[tan^2x(1+tan^2x)]sec^2x=[tan^2x(sec^2x)]sec^2x=tan^2x(sec^2x·sec^2x)=tan^2x~sec^4x$