Answer
If $f(x)$ is an even function then $h(x)=[f(x)]^2$ is also an even function.
Work Step by Step
If $f(x)$ is an even function, then $f(-x)=f(x)$.
$h(-x)=[f(-x)]^2=[f(x)]^2=h(x)$
If $h(-x)=h(x)$, we can conclude that $h(x)$ is an even function.
